JAMB - Physics (2006 - No. 21)

If the radius of the earth is 6.4 x 10\(^6\)m, the escape velocity of a satellite from the earth is?

[g = 10 ms-2]

1.13 x 10⁴ ms^-1

9.00 x 10³ ms^-1

8.00 x 10³ ms^-1

1.27 x 10⁴ ms^-1

V = √2GM/R.

=√[2 x 6.67 x 10\(^{-11}\) x 6.0 x 10\(^24\)] / 6.4 x 10\(^6\)

= √12.506 x 10\(^7\)

= 11,183.13

V =√2gR

V=√[2 * 10 * 6.4 x 10\(^6\)]

V = √128,000,000

11,313.708