JAMB - Physics (2005 - No. 7)
An object is projected from a height of 80 m above the ground with a velocity of 40ms-1 at an angle of 30° to the horizontal. The time of flight [ g ≈ 10m/s\(^2\)
8 s
4 s
16 s
10 s
Explanation
for a body projected at an angle θ to the horizontal, the time of the flight is given by T = (2u sin θ)/g =(2x 40)x sin (30)/10 =(2 x 40) x (0.5)/10 = 4.0secs.
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