JAMB - Physics (2004 - No. 29)

the diagram above shows forces 4N, 6N, 10N and 8N which act at a point O in the directions indicated. the net horizontal force is

13N

17N

√3N

7√3N

Explanation

Component of 8N along the horizontal = 8 cos 60^o = 8 x 0.5
= 4N
Similarity Component of 6N along the horizontal = 6 cos 60^o = 3N
∴ Total force towards the right = 10 + 4 + 3
= 17N
Again total force toward the left = 4N
∴ Net horizontal force (towards the right) = 17-4
= 13N

JAMB - Physics (2004 - No. 29)

Explanation

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