JAMB - Physics (2004 - No. 27)
A 100kg box is pushed along a road with force of 500N. If the box moves with a uniform velocity, the coefficient of friction between the box and the road is
0.4
1.0
0.8
0.5
Explanation
Coefficient of friction μ = F/R = F/mg = 500/1000 = 0.5
∴ μ = 0.5
∴ μ = 0.5
Comments (0)
