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JAMB - Physics (2001 - No. 42)

The diagram above shows two capacitors P and Q of capacitance 2μF and 4μF respectively connected to a d.c source. The ratio of energy stored in P to Q is
4:1
2:1
1:4
1:2

Explanation

Energy = 1/2CV2
∴Energy of P = 1/2 x 2 x V2 = V2
Energy of Q = 1/2 x 4 x V2 = 2V2
∴ P/Q = V2/2V2 = 1/2 => P:Q = 1:2

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