JAMB - Physics (2001 - No. 24)
The ratio of electrostatic force F\(_E\) to gravitational force F\(_G\) between two protons each of charge e and mass m, at a distance d is
\(\frac{e}{4πε_oGm}\)
\(\frac{e^2}{Gm^2}\)
\(\frac{Gm^2}{4πε_oe^2}\)
\(\frac{e^2}{4πε_oGm^2}\)
Explanation
Electrostatic force = F\(_E\) = \(\frac{e^2}{4πε_od^2}\)
Gravitational force = F\(_G\) = \(\frac{Gm^2}{d^2}\)
\(\frac{F_E}{F_G}\) = \(\frac{\frac{e^2}{4πε_od^2}}{\frac{Gm^2}{d^2}}\) = \(\frac{e^2}{4πε_oGm^2}\)
NOTE: (d\(^2\)s canceled out)
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