JAMB - Physics (2001 - No. 12)

The pressure of a given mass of a gas changes from 300Nm\(^{-2}\) to 120Nm\(^{-2}\) while the temperature drops from 127°C to -73°C. The ratio of the final volume to the initial volume is
2 : 5
5 : 4
4 : 5
5 : 2

Explanation

To find the ratio of the final volume to the initial volume of a gas when both pressure and temperature change, we can use the Ideal Gas Law, which states that

\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}\)

P\(_1\) = 300N/m\(^2\) V\(_1\) =  ?, V\(_2\) =  ?, T\(_1\) = 127°C =127+273 = 400K,  T\(_2\)  = −73°C = −73 + 273 = 200K

P\(_2\) = 120N/m\(^2\) 

Using the Ideal Gas Law, we can rearrange it to find the ratio of volumes:

 = \(\frac{V_2}{V_1} =  \frac{P_1T_2}{P_2T_1}\)

= \(\frac{V_2}{V_1} =  \frac{300 \times 200}{120 \times 400}\) = \(\frac{5}{4}\)

Therefore, V\(_2\) : V\(_1\) = 5 : 4.

 

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