JAMB - Physics (2000 - No. 7)
A stream is flowing at 0.75ms\(^{-1}\) and a boat heading perpendicular for the stream landed at the opposite bank at an angle of 30°. Calculate the velocity of the boat.
1.50ms-1
1.00ms-1
0.86ms-1
0.65ms-1
Explanation
Let the velocity of stream be Vs = 0.75m/s
Angle at which the boat lands θ = 30º
the velocity of the boat = Vb
\(\frac{0.75}{V_b}\) = Sin30º = 0.5
∴ V\(_b\) = \(\frac{0.75}{0.5}\) = 1.5m/s
Comments (0)
