JAMB - Physics (1999 - No. 9)
A solid weigh 10 .00 N in air, 6 N when fully immersed in water and 7 . 0 N when fully immersed in a liquid X. Calculate the relative density of the liquid, X.
5/3
4/3
3/4
7/10
Explanation
R.D = \(\frac{\text{loss in weight in liquid X}}{\text{ loss in weight in water}}\)
R.D = \(\frac{(10 - 7)}{(10 - 6)}\) = \(\frac{3}{4}\)
R.D = \(\frac{(10 - 7)}{(10 - 6)}\) = \(\frac{3}{4}\)
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