JAMB - Physics (1997 - No. 3)

A 5kg block is released from rest on a smooth plane inclined at an angle of 30o to the horizontal. What is the acceleration down the plane? [g = 10ms-2]
5.0 ms-2
5.8 ms-2
8.7 ms-2
25.0 ms-2

Explanation

ma = mgsin\(\theta\)

a = \(\frac{5 {\times} 10 {\times} sin30}{t}\)

a = 5ms2

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