JAMB - Physics (1997 - No. 18)
Before starting a journey, the tyre pressure of a car was 3 x 105Nm-2 at 27oC. At the end of the journey, the pressure rose to 4 x 105Nm-2. Calculate the temperature of the tyre after the journey, assuming the volume is constant
400oC
300oC
273oC
127oC
Explanation
\(\frac{P_1}{T_1}\) = \(\frac{ P_2}{T_2}\)
\(\frac{3 \times\ 10^6}{27 + 273}\) = \(\frac{4 \times\ 10^6}{0 + 273}\)
\(\theta\) = 127oC
\(\frac{3 \times\ 10^6}{27 + 273}\) = \(\frac{4 \times\ 10^6}{0 + 273}\)
\(\theta\) = 127oC
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