JAMB - Physics (1995 - No. 29)

Two parallel plates at a distance of 8.0 x 10-3m apart are maintained at a p.d of 600 volts with the negative plate earthed. What is the electric field strength?
4.8 Vm-1
75.0Vm-1
4800.0Vm-1
75000.0Vm-1

Explanation

E = \(\frac{voltage}{distance}\)

= \(\frac{600}{8 \times 10^2}\)

= 75000.0Vm-1

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