JAMB - Physics (1994 - No. 33)
A capacitor 8\(\mu\)F is charged to a potential difference of 100V. The energy stored by the capacitor is
1.0 x 104J
8.0 x 10J
1.25 x 10J
4.0 x 10-2J
Explanation
Energy = \(\frac{1}{2}\)CV2
= \(\frac{1}{2}\) x 8 x 10-6 x (100)2
= 4 x 10-2J
= \(\frac{1}{2}\) x 8 x 10-6 x (100)2
= 4 x 10-2J
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