JAMB - Physics (1992 - No. 14)
How much heat is absorbed when a block of copper of mass 0.05kg and specific heat capacity 390Jkg-1K-1 is heated from 20oC to 70oC?
39 . 98 x 10-1J
9.75 x 102J
3.98 x 103J
9.75 x 103J
Explanation
Q = mc\(\theta\)
= 0.05 x 390 x (70 - 20)
= 975J
= 0.05 x 390 x (70 - 20)
= 975J
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