JAMB - Physics (1990 - No. 45)
What is the average velocity of the sprinter whose velocity time graph is as shown above
85.0ms-1
17.0ms-1
8.5ms-1
1.7ms-1
Explanation
Average velocity = \(\frac{total speed}{total time}\)
Total distance = Area under the graph i.e area of trapezium = \(\frac{1}{2}\)(a + b) x h
= 0.5(6 + 10) x 10 = 80m
Total time = 10secs
Average velocity = \(\frac{total speed}{total time}\) = \(\frac{80}{10}\) = 8m/s
so closest answer is 8.5m/s
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