JAMB - Physics (1990 - No. 37)
A lamp is rated 240V, 60W. The resistance of the filament is
960\(\Omega\)
16\(\Omega\)
15\(\Omega\)
4\(\Omega\)
Explanation
P = \(\frac{V_2}{R}\) \(\Rightarrow\) R = \(\frac{V_2}{p}\)
= \(\frac{240\times 240}{60}\)
= 960\(\Omega\)
= \(\frac{240\times 240}{60}\)
= 960\(\Omega\)
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