JAMB - Physics (1990 - No. 32)
When a known standard resistor of 2\(\Omega\) is connected to the 0.0cm end of a meter bridge, the balance point is found to be at 55.0cm. What is the value of the unknown resistor?
1.10\(\Omega\)
1.64\(\Omega\)
2.44\(\Omega\)
27.50\(\Omega\)
Explanation
\(\frac{R_1}{R_2}\) = \(\frac{L_1}{R_2}\)
\(\frac{2}{R_2}\) = \(\frac{55}{45}\)
R = 1.64\(\Omega\)
\(\frac{2}{R_2}\) = \(\frac{55}{45}\)
R = 1.64\(\Omega\)
Comments (0)
