JAMB - Physics (1987 - No. 45)
A 50kg block is dropped from a point 10m above as shown in the fig above. if the force constant of the spring is 4.0 x 10\(^4\)Nm-1, find the maximum compression of the spring
[g = 10ms-2]
1.25m
0.50m
0.25m
0.05m
Explanation
P.E\(_{mgh}\) = \(\frac{1}{2}\) * k * x\(^2\)
mgh = \(\frac{1}{2}\) * k * x\(^2\)
50 * 10 * 10 = \(\frac{1}{2}\) * 4 * 10\(^4\) * x\(^2\)
→ x\(^2\) = \(\frac{5000 * 2}{4 * 10^4}\)
→ x = √[0.25]
: x = 0.50m
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