JAMB - Physics (1987 - No. 24)
The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 150Hz?
1
2
3
4
Explanation
The fundamental frequency (Fo) = 40Hz
First overtone f1 = 2 \(\times\) 40 = 80
Second overtone f2 = 3 \(\times\) 40 = 120
Third overtone f3 = 4 \(\times\) 40 = 160.
Hence there are just two overtones between 40Hz and 150Hz
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