JAMB - Physics (1986 - No. 39)

In fig 9 the value of R is

3Ω
4Ω
5Ω
6Ω

Explanation

From Ohm's law, V = IR

But R = total resistance of the circuit.

12 = 2( 3 + \(R_{parallel}\))

12 = 2(3 + \(\frac{6R}{6 + R}\))

6 = \(\frac{18 + 3R + 6R}{6 + R}\)

36 + 6R = 18 + 9R

9R - 6R = 36 - 18

3R = 18

R = \(\frac{18}{3}\) = 6 \(\Omega\)

 

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