JAMB - Physics (1986 - No. 39)

In fig 9 the value of R is
3Ω
4Ω
5Ω
6Ω
Explanation
From Ohm's law, V = IR
But R = total resistance of the circuit.
12 = 2( 3 + \(R_{parallel}\))
12 = 2(3 + \(\frac{6R}{6 + R}\))
6 = \(\frac{18 + 3R + 6R}{6 + R}\)
36 + 6R = 18 + 9R
9R - 6R = 36 - 18
3R = 18
R = \(\frac{18}{3}\) = 6 \(\Omega\)
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