JAMB - Physics (1986 - No. 26)
A wave of frequency 10Hz forms a stationary wave pattern in a medium where the velocity is 20cms-1. The distance between adjacent nodes is
1.0cm
1.5cm
2.0cm
5.0cm
Explanation
\(\lambda\) = \(\frac{v}{f}\)
= \(\frac{20}{10}\)
= 2cm ; distance between adjacent nodes
= 2cm \ 2
= 1cm
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