JAMB - Physics (1985 - No. 34)
If the distance between two stationary charged particle is doubled, the magnitude of the electro-static force between them will be
doubled
halved
a quarter of its former value
unchanged
four times the original value
Explanation
F \(\alpha\) \(\frac{1}{d^2}\)
F x d2 = constant
F1 x (d1)2 = F2 x (d2)2
d2 = 2d1
F1 x (d1)2 = F2 x (2d1)2
F2 = \(\frac{1}{4}\)F1
F x d2 = constant
F1 x (d1)2 = F2 x (d2)2
d2 = 2d1
F1 x (d1)2 = F2 x (2d1)2
F2 = \(\frac{1}{4}\)F1
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