JAMB - Physics (1984 - No. 29)

A gun of mass 2.0kg fires a bullet of mass 16 x 10 -2kg due East. If the bullet leaves the nozzle of the gun with a velocity of 150ms-1, what is the recoil velocity of the gun?
150ms-1 due West
1.2 x 10-4ms-1 due West
1.2ms-1 due West
1.2ms-1 due East
150ms-1 due East

Explanation

Gun momentum = bullet momentum

2 x v = 1.6 x 10-2 x 150

v = 1.2ms-1 in opposite direction

Comments (0)

Advertisement