JAMB - Physics (1984 - No. 18)
A plane inclined at an angle of 30o to the horizontal has an efficiency of 60%. The force parallel to the plane required to push a load of 120N uniformly up the plane is
60N
100N
120N
200N
240N
Explanation
V.R = \(\frac{1}{sin 30}\) = 2
Efficiency = \(\frac{m.A}{V.R}\) x 100%
60 = \(\frac{120}{effort}\) x \(\frac{1}{2}\) x 100
Effort = 100N
Efficiency = \(\frac{m.A}{V.R}\) x 100%
60 = \(\frac{120}{effort}\) x \(\frac{1}{2}\) x 100
Effort = 100N
Comments (0)
