JAMB - Physics (1978 - No. 5)
A piece of rubber 10cm long stretches 6mm when a load of 100N is hung from it. What is the strain?
60
6
6 x 10-2
6 x 10-3
0.6
Explanation
Strain = \(\frac{\Delta L}{L}\)
Extension produced = 6mm or 0.6cm
Original length = 10cm
= \(\frac{0.6}{10}\)
= 0.06 or 6 x 10\(^{-2}\)
Comments (0)
