JAMB - Physics (1978 - No. 16)

A temperature 20°C is the same as

36^oF

68^oF

11.1^oF

43.1^oF

25^oF

212°F ... 100°C

\(\theta\)°F ... 20°C

32°F ... 0°C

\(\frac{\theta - 32}{212 - 32}\) = \(\frac{20 - 0}{100 - 0}\)

180 = 5(\(\theta\) - 32)

5\(\theta\) = 180 + 160 = 340

\(\theta\) = 68°F