JAMB - Mathematics (2025 - No. 8)
Given that Cos A = \(\frac{12}{13}\) for 0 ≤ A ≤ 90º, find Tan A.
\(\frac{5}{12}\)
\(\frac{12}{13}\)
\(\frac{5}{13}\)
\(\frac{13}{12}\)
Explanation
Sin A = \(\sqrt{(1 - (\frac{12}{13})^2)}\) = \(\sqrt{(1 - \frac{144}{169}}\))
= \(\sqrt{(\frac{25}{169})}\) = \(\frac{5}{13}\).
Tan A = (\(\frac{5}{13}\)) \(\div\) (\(\frac{12}{13}\)) = \(\frac{5}{12}\).
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