JAMB - Mathematics (2025 - No. 45)
Solve x\(^2\) + 3x - 4 ≤ 0
-4 \(\geq\) x \(\geq\) 1
4 \(\leq\) x \(\leq\) - 1
4 \(\geq\) x \(\geq\) 1
\(- 4 \leq x \leq 1\)
Explanation
To solve \(x^2 + 3x - 4 \leq 0\):
Factorize: \((x + 4)(x - 1) \leq 0\)
Roots: \(x = -4\), \(x = 1\)
Solution: \(-4 \leq x \leq 1\) .
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