JAMB - Mathematics (2025 - No. 21)
In a basket of fruits, there are 6 grapes, 11 bananas, and 13 oranges. If one fruit is chosen at random, what is the probability that the fruit is either a grape or a banana?
\(\frac{17}{30}\)
\(\frac{11}{30}\)
\(\frac{6}{30}\)
\(\frac{5}{30}\)
Explanation
Total fruits = 6 + 11 + 13 = 30
Favorable (grape or banana) = 6 + 11 = 17
Probability = \(\frac{17}{30}\)
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