JAMB - Mathematics (2025 - No. 18)
Obtain the equation of a straight line passing through (3, 15) whose slope = 3\(\frac{1}{5}\).
5y + 16x + 27 = 0
5y - 16x + 27 = 0
5y - 16x - 27 = 0
5y + 16x - 27 = 0
Explanation
Convert the mixed number slope to an improper fraction: 3 \(\frac{1}{5} = \frac{16}{5}\)
Use the point-slope form with the given point (3,15)
y - 15 = \(\frac{16}{5}\)(x - 3)
Multiply both sides by 5 to clear the fraction: 5(y−15) = 16(x−3)
5y − 75 = 16x − 48
Rearrange terms to standard form: 5y − 16x − 75 + 48 = 0
5y − 16x − 27 = 0
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