JAMB - Mathematics (2024 - No. 17)
From the top of a building 10m high, the angle of elevation of a fruit on top of a tree 25m is 30º. Calculate the horizontal distance between the building and the tree.
15\(\sqrt{3}\)m
5\(\sqrt{3}\)m
25\(\sqrt{3}\)m
30\(\sqrt{3}\)m
Explanation
From the diagram above:
Tan 30º = \(\frac{15}{x}\)
\(\frac{\sqrt{3}}{3}\) = \(\frac{15}{x}\)
x\(\sqrt{3}\) = 3 x 15 = 45
x = \(\frac{45\sqrt{3}}{3}\) = 15\(\sqrt{3}\)m ( this is after rationalizing the denominator)
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