JAMB - Mathematics (2024 - No. 13)
Let A = \(\begin{pmatrix}2 & -4 & 3\\5 & 1 & 0\end{pmatrix}\) and B = \(\begin{pmatrix}1 & 4 & -2\\-3 & 3 & -1\end{pmatrix}\). Find A + 2B
\(\begin{pmatrix}4 & 4 & -1\\-1 & 7 & -2\end{pmatrix}\)
\(\begin{pmatrix}-1 & 4 & -1\\4 & 7 & -2\end{pmatrix}\)
\(\begin{pmatrix}4 & 4 & -1\\7 & 7 & -2\end{pmatrix}\)
\(\begin{pmatrix}-1 & 7 & -2\\4 & 4 & -2\end{pmatrix}\)
Explanation
A = \(\begin{pmatrix}2 & -4 & 3\\5 & 1 & 0\end{pmatrix}\), B = \(\begin{pmatrix}1 & 4 & -2\\-3 & 3 & -1\end{pmatrix}\)
2B = 2 x \(\begin{pmatrix}1 & 4 & -2\\-3 & 3 & -1\end{pmatrix}\) = \(\begin{pmatrix}2 & 8 & -4\\-6 & 6 & -2\end{pmatrix}\)
A + 2B = \(\begin{pmatrix}2 & -4 & 3\\5 & 1 & 0\end{pmatrix}\) + \(\begin{pmatrix}2 & 8 & -4\\-6 & 6 & -2\end{pmatrix}\) = \(\begin{pmatrix}4 & 4 & -1\\-1 & 7 & -2\end{pmatrix}\)
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