JAMB - Mathematics (2019 - No. 58)
Integrate \(\int (4x^{-3} - 7x^2 + 5x - 6) \mathrm d x\).
\(-2x^{-2} - \frac{7}{3}x^3 + \frac{5}{2} x^2 - 6x\)
\(2x^2 + \frac{7}{3} x^3 - 5x + 6\)
\(12x^2 + 14x - 5\)
\(-12x^{-4} - 14x + 5\)
Explanation
\(\int (4x^{-3} - 7x^2 + 5x - 6) \mathrm d x\)
= \(\frac{4x^{-3 + 1}}{-3 + 1} - \frac{7x^{2 + 1}}{2 + 1} + \frac{5x^{1 + 1}}{1 + 1} - 6x\)
= \(-2x^{-2} - \frac{7}{3} x^3 + \frac{5}{2} x^2 - 6x\)
Comments (0)
