JAMB - Mathematics (2019 - No. 26)
If \(f(x) = 3x^3 + 4x^2 + x - 8\), what is the value of f(-2)?
-24
30
-18
-50
Explanation
\(f(x) = 3x^3 + 4x^2 + x - 8\)
\(f(-2) = 3(-2)^3 + 4(-2)^2 + (-2) - 8\)
= \(-24 + 16 - 2 - 8\)
= -18
Comments (0)
\(f(x) = 3x^3 + 4x^2 + x - 8\)
\(f(-2) = 3(-2)^3 + 4(-2)^2 + (-2) - 8\)
= \(-24 + 16 - 2 - 8\)
= -18
