\(4\sin^2 x - 3 = 0\)

\(4 \sin^2 x = 3 \implies \sin^2 x = \frac{3}{4}\)

\(\sin x = \frac{\sqrt{3}}{2}\)

\(\therefore x = \sin^{-1} (\frac{\sqrt{3}}{2})\)

x = 60°