JAMB - Mathematics (2018 - No. 15)
Make T the subject of the relation.
T = \(\frac{R + P3}{15Q}\)
T = \(\frac{R - 15P^3}{Q}\)
T =R - \(\frac{15P^3}{Q}\)
T = \(\frac{15R + Q}{P^3}\)
Explanation
P = (\(\frac{Q( R - T )}{ 15})^\frac{1}{3}\)
take cube of both sides
\(P^3 =\frac{Q( R - T)}{ 15}\)
cross multiply
\(15P^3 = Q( R - T)\)
\(\frac{15P^3}{Q}\) = R - T
T = R - \(\frac{15P^3}{Q}\)
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