JAMB - Mathematics (2015 - No. 13)
Find the equation of a line which is form origin and passes through the point (−3, −4)
y = \( \frac{3x}{4} \)
y = \( \frac{4x}{3} \)
y = \( \frac{2x}{3} \)
y = \( \frac{x}{2} \)
Explanation
The slope of the line from (0, 0) passing through (-3, -4) = \(\frac{-4 - 0}{-3 - 0}\)
= \(\frac{4}{3}\)
Equation of a line is given as \(y = mx + b\), where m = slope and b = intercept.
To get the value of b, we use a point on the line, say (0, 0).
\(y = \frac{4}{3} x + b\)
\(0 = \frac{4}{3}(0) + b\)
\(b = 0\)
The equation of the line is \(y = \frac{4}{3} x\)
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