JAMB - Mathematics (2014 - No. 25)
Find the mid point of S(-5, 4) and T(-3, -2)
-4, 2
4, -2
-4, 1
4, -1
Explanation
Mid point of S(-5, 4) and T(-3, -2) is
\([\frac{1}{2}(-5 + -3), \frac{1}{2}(4 + (-2))]\)
\([\frac{1}{2}(x_1 + x_2), \frac{1}{2}(y_1 + y_2)]\)
\([\frac{1}{2}(-8), \frac{1}{2}(2)]\)
\([-4, 1]\)
\([\frac{1}{2}(-5 + -3), \frac{1}{2}(4 + (-2))]\)
\([\frac{1}{2}(x_1 + x_2), \frac{1}{2}(y_1 + y_2)]\)
\([\frac{1}{2}(-8), \frac{1}{2}(2)]\)
\([-4, 1]\)
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