JAMB - Mathematics (2013 - No. 33)

In the diagram given, find the value of x.
30o
40o
45o
15o

Explanation

In the diagram above, < CDE = < CED = 15o

(base < s of isos. \(\bigtriangleup\))

< ECD = 180o - (15 + 15)o

= 180o - 30o = 150o

But x + 110o = 150o

(Sum of opp. interior < s of a\(\bigtriangleup\) = opp. exterior < )

x = 150o - 110o = 40o

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