JAMB - Mathematics (2011 - No. 42)
Find the probability that a number picked at random from the set(43, 44, 45, ..., 60) is a prime number.
\(\frac{2}{3}\)
\(\frac{1}{3}\)
\(\frac{2}{9}\)
\(\frac{7}{9}\)
Explanation
Prime numbers = (43,47,53,59)
N = (43, 44, 45,..., 60)
The universal set contains 18 numbers.
The prime numbers between 43 and 60 are 4
Probability of picking a prime number = \(\frac{4}{18}\)
= \(\frac{2}{9}\)
N = (43, 44, 45,..., 60)
The universal set contains 18 numbers.
The prime numbers between 43 and 60 are 4
Probability of picking a prime number = \(\frac{4}{18}\)
= \(\frac{2}{9}\)
Comments (0)
