JAMB - Mathematics (2011 - No. 31)

A man walks 100 m due West from a point X to Y, he then walks 100 m due North to a point Z. Find the bearing of X from Z.
195o
135o
225o
045o

Explanation

tan\(\theta\) = \(\frac{100}{100}\) = 1

\(\theta\) = tan-1(1) = 45o

The bearing of x from z is N45oE or 135o

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