JAMB - Mathematics (2010 - No. 29)
Make Q the subject of formula if p = \(\frac{M}{5}\)(X + Q) + 1
\(\frac{5P - MX + 5}{M}\)
\(\frac{5P - MX - 5}{M}\)
\(\frac{5P + MX + 5}{M}\)
\(\frac{5P + MX - 5}{M}\)
Explanation
p = \(\frac{M}{5}\)(X + Q) + 1
P - 1 = \(\frac{M}{5}\)(X + Q)
\(\frac{5}{M}\)(p - 1) = X + Q
\(\frac{5}{M}\)(p - 1)- x = Q
Q = \(\frac{5(p -1) - Mx}{M}\)
= \(\frac{5p - 5 - Mx}{M}\)
= \(\frac{5p - Mx - 5}{M}\)
P - 1 = \(\frac{M}{5}\)(X + Q)
\(\frac{5}{M}\)(p - 1) = X + Q
\(\frac{5}{M}\)(p - 1)- x = Q
Q = \(\frac{5(p -1) - Mx}{M}\)
= \(\frac{5p - 5 - Mx}{M}\)
= \(\frac{5p - Mx - 5}{M}\)
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