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JAMB - Mathematics (2010 - No. 17)
Find ∫(sin x + 2)dx
cos x + x
2
+ K
cos x 2x + K
-cos x + x
2
+ K
-cos x + 2x + K
Explanation
∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx
= -cos χ + 2χ + K
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