Area of a triangle = \(\frac{1}{2}\) ab Sinθ
12\(\sqrt{3}\) = \(\frac{1}{2}\) x 8 x q sin 60
12\(\sqrt{3}\) = 4 x q x \(\frac{\sqrt{3}}{2}\)
12\(\sqrt{3}\) = 2q\(\sqrt{3}\)

q = \(\frac{12\sqrt{3}}{2\sqrt{3}}\)

q = 6cm.