JAMB - Mathematics (2010 - No. 11)

From the cyclic quadrilateral TUVW above, find the value of x

26^o

24^o

20^o

23^o

TUVW is a cyclic quad
3χ + 20 + 88 = 180 (opp ∠ s of a cyclic quad are supplementary)
3χ + 108 = 180
3χ = 180 - 108
3χ = 72
χ = 72/3
χ = 24o