JAMB - Mathematics (2009 - No. 29)
What is the locus of the mid-point of all the chords of length 6cm with circle of radius 5cm and with center O?
A circle of radius 4 cm and the center 0
The perpendicular bisector of the chords
A straight line passing through 0
A circle of radius 6 cm and with center 0
Explanation
x\(^2\) + 3\(^3\) = 5\(^2\)
x\(^2\) + 9 = 25
x\(^2\) = 25 – 9
x\(^2\) = 16
x = √ 16
= 4 cm
∴ The locus is a circle of radius 4 cm with the center O
Comments (0)
