JAMB - Mathematics (2008 - No. 38)
What is the mean of the data t, 2t-1, t-2, 2t -1, 4t and 2t+2?
2t
2t-1
2/3t+1
2t-1/3
Explanation
\(Mean = \frac{t+2t-1+t-2+2t-1+4t+2t+2}{6}\)
Mean = \(\frac{12t-2}{6}\)
=\(\frac{2(6t-1)}{6}\)
=\(\frac{6t-1}{3}\)
=\(\frac{6t}{3}- \frac{1}{3}\)
=2t-\(\frac{1}{3}\)
Mean = \(\frac{12t-2}{6}\)
=\(\frac{2(6t-1)}{6}\)
=\(\frac{6t-1}{3}\)
=\(\frac{6t}{3}- \frac{1}{3}\)
=2t-\(\frac{1}{3}\)
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