JAMB - Mathematics (2007 - No. 35)
If the lines 3y = 4x - 1 and qy = x + 3 are parallel to each other, the value of q is
-4/3
-3/4
4/3
3/4
Explanation
If the line 3y = 4x – 1 is parallel t[ line qy = x + 3
Implies gradient of 3y = 4x – 1
Y = 4/3x - 1/3
∴Gradient = 4/3
Gradient of line qy = x + 3
Y = 1/qx + 3/q
∴ Gradient = 1/q
4/3 = 1/q
4q = 3
Q = 3/4
Implies gradient of 3y = 4x – 1
Y = 4/3x - 1/3
∴Gradient = 4/3
Gradient of line qy = x + 3
Y = 1/qx + 3/q
∴ Gradient = 1/q
4/3 = 1/q
4q = 3
Q = 3/4
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