JAMB - Mathematics (2003 - No. 40)

In the diagram above, PQR is a straight line and PS is a tangent to the circle QRS with /PS/ = /SR/ and ∠SPR = 40°. Find ∠PSQ

40^o

30^o

20^o

10^o

R = P (base ∠s of isc Δ, ps = RS)
∴R = 40°
∠PSQ = R (∠s in alternate segment)
∴∠PSQ = 40°