JAMB - Mathematics (2001 - No. 20)
The bearings of P and Q from a common point N are 020° and 300° respectively. If P and Q are also equidistant from N, find the bearing of P from Q.
040°
070°
280°
320°
Explanation
From the diagram above, <PNQ = 80º
But < PQN = <NPQ = 50º ( base <s of isosceles triangle PQN)
Therefore, the bearing of P from Q = 070º
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